# Boyle's Law: Volume Calculation

## How can we calculate the volume of air inside a tire under different pressures?

What would the volume of air inside a 40.0 L tire under 218 kPa of pressure occupy if it all escaped into a balloon at 101.3 kPa?

## Volume Calculation using Boyle's Law

The volume of air inside a 40.0 L tire under 218 kPa of pressure that would occupy at 101.3 kPa pressure is 86.1 L.

Boyle's Law states that the pressure and volume of a gas are inversely proportional when temperature is held constant. This means that if the pressure of a gas decreases, its volume will increase, and vice versa.

To calculate the volume of air inside a tire under different pressures, we can use Boyle's Law formula:

**P₁V₁ = P₂V₂**

Where P₁ is the initial pressure, V₁ is the initial volume, P₂ is the final pressure, and V₂ is the final volume.

In the given scenario, the initial pressure (P₁) is 218 kPa, the initial volume (V₁) is 40.0 L, and the final pressure (P₂) is 101.3 kPa. We need to calculate the final volume (V₂).

By rearranging the formula, we get:

**V₂ = (P₁ x V₁) / P₂**

Substitute the values into the formula:

**V₂ = (218 kPa x 40.0 L) / 101.3 kPa = 86.1 L**

Therefore, the volume of air inside a 40.0 L tire under 218 kPa of pressure would occupy 86.1 L if it all escaped into a balloon at 101.3 kPa.