# Calculate the mole fraction of each solute and solvent

What is the mole fraction of H₂SO₄ and water in a solution containing 583 g of H₂SO₄ in 1.50 kg of water?

The mole fraction of sulphuric acid (H₂SO₄) in the solution is 0.067 while the mole fraction of water (H₂O) is 0.933.

## Explanation:

**Firstly**, we need to convert the masses of H₂SO₄ and water into moles. The molar mass of H₂SO₄ (sulphuric acid) is about 98.08 g/mol. Therefore, 583 g of H₂SO₄ is approximately 5.95 moles. For water (H₂O), the molar mass is about 18.015 g/mol. Therefore, 1.50 kg or 1500 g of water is about 83.2 moles. To calculate the mole fraction, we divide the number of moles of solute (H₂SO₄) by the total number of moles (H₂SO₄ + H₂O). So, the mole fraction of H₂SO₄ is calculated as follows: Mole fraction of H₂SO₄ = moles of H₂SO₄ / (moles of H₂SO₄ + moles of H₂O) Mole fraction of H₂SO₄ = 5.95 / (5.95 + 83.2) = 0.067 Similarly, the mole fraction of water (H₂O) can be calculated as: Mole fraction of H₂O = moles of H₂O / (moles of H₂SO₄ + moles of H₂O) Mole fraction of H₂O = 83.2 / (5.95 + 83.2) = 0.933 Therefore, the mole fraction of H₂SO₄ in the solution is 0.067 and the mole fraction of water is 0.933. For further information on Mole Fraction and its calculations, you can refer to the following link: