# Calculate the Volume of a Gas at Standard Temperature

## Explanation:

**Given data:**

Initial temperature = 9Â°C (9+273 = 282 K)

Initial volume of gas = 6.17 L

Final volume of gas = ?

Final temperature = standard = 273 K

**Solution:**

**Formula:**

The Charles Law will be applied to solve the given problem. According to this law, 'the volume of a given amount of gas is directly proportional to its temperature at a constant number of moles and pressure'.

**Mathematical expression:**

Vâ/Tâ = Vâ/Tâ

Vâ = Initial volume

Tâ = Initial temperature

Vâ = Final volume

Tâ = Final temperature

Now we will put the values in the formula:

Vâ/Tâ = Vâ/Tâ

Vâ = VâTâ/Tâ

Vâ = 6.17 L Ã 273 K / 282 K

Vâ = 1684.41 L.K / 282 K

Vâ = 5.97 L