# Chemistry Problem: Diluting Nitric Acid Solution

## How much 16.0 M nitric acid is needed to prepare a 0.75 M nitric acid solution?

In order to prepare 175 mL of a 0.75 M nitric acid solution, how many milliliters of 16.0 M nitric acid are required?

## Answer:

To prepare a 0.75 M nitric acid solution with a volume of 175 mL, you would need to use 8.23 mL of a 16.0 M nitric acid solution.

When preparing a diluted solution from a concentrated one, we can use the formula C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Plugging in the given values:

**Initial concentration (C1): 16.0 M**

**Initial volume (V1): unknown**

**Final concentration (C2): 0.75 M**

**Final volume (V2): 175 mL**

We can then solve for the unknown initial volume (V1) using the formula:

**(16.0 M) * (V1) = (0.75 M) * (175 mL)**

**V1 = (0.75 M * 175 mL) / 16.0 M**

**V1 = 8.23 mL**

Therefore, to prepare 175 mL of a 0.75 M nitric acid solution, you would need to mix 8.23 mL of 16.0 M nitric acid solution with the appropriate amount of water or solvent to reach the final volume.