# How to Calculate the Inductance of a Solenoid with Specific Parameters

## What is the inductance of a solenoid 300 cm long, with 10.0 turns of wire and a cross-sectional area of 1.00 × 10^-4 m2?

A. 4.19 fH B. 4.19 µH C. 4 19 pH D. 4 19 nH E. 4.19 mH

## Answer:

The inductance of the solenoid is 4.19 m-H (option E).

Inductance is an essential parameter in electromagnetism, especially when dealing with solenoids. In this case, we are tasked with finding the inductance of a solenoid that is 300 cm long, with 10.0 turns of wire, and a cross-sectional area of 1.00 × 10^-4 m2.

The formula to calculate the inductance of a solenoid is L=μn²A/λ, where L is the inductance of the solenoid, n is the number of turns, A is the cross-sectional area, λ is the length of the solenoid, and μ is the magnetic permeability of the material used.

Given the parameters provided, we can substitute the values into the formula to find the inductance of the solenoid. After performing the calculations, the inductance is determined to be 4.19 m-H, which corresponds to option E.

Understanding how to calculate inductance in different scenarios can be beneficial in various applications of electromagnetism and electrical engineering.