# Equilibrium Concentration Calculation in a Chemical Reaction

## Introduction

In a chemical reaction at 445 °C, the equilibrium constant (Kc) is determined to be 50.2. Initially, the reaction mixture contains 0.100 M of H2 (g), 0.100 M of I2 (g), and 0.0500 M of HI (g). We are tasked with calculating the equilibrium concentration of HI at the given temperature.

## Equilibrium Concentration Calculation

To calculate the equilibrium concentration of HI, we can use the equilibrium constant expression:

**K = 50.2 = (2x)^2 / (0.1-x)^2**

After solving the equation, we find that x = 0.078. Therefore, the equilibrium concentration of HI is 0.078 M.

## Conclusion

By using the given equilibrium constant and initial concentrations of reactants, we were able to determine the equilibrium concentration of HI in the chemical reaction. This calculation is crucial in understanding the composition of a system at equilibrium.

At 445 °C, Kc = 50.2. If one starts with 0.100 M H2 (g), 0.100 M I2 (g) and 0.0500 M HI (g) what is the equilibrium concentration of HI?

K = 50.2 = (2x)^2 / (0.1-x)^2 x = 0.078 Therefore, the equilibrium concentration of HI is 0.078 M Hope this helped! :D